If the distance between two suspended masses 10kg each is tripled, the gravitational force of attraction between them is reduced by
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Correct Answer: Option D
Explanation:
Let the distance apart the two masses = m.
From the equation F & M1 m2/Ï’2
F1 α 10 x 10/ϒ2 = F α 100/ ϒ2
F2 α 10 X 10/(3ϒ)2 => F2 α 100/9ϒ2
therefore F2/F1 = 100/9Ï’2/100/Ï’2 = 100/9Ï’2 Ï’2/100 = 1/9
Therefore F 2 : F 1 = 1 : 9
Let the distance apart the two masses = m.
From the equation F & M1 m2/Ï’2
F1 α 10 x 10/ϒ2 = F α 100/ ϒ2
F2 α 10 X 10/(3ϒ)2 => F2 α 100/9ϒ2
therefore F2/F1 = 100/9Ï’2/100/Ï’2 = 100/9Ï’2 Ï’2/100 = 1/9
Therefore F 2 : F 1 = 1 : 9