The energy stored in a capacitor of capacitance 10μF carrying a charge of 100μC
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Correct Answer: Option D
Explanation:
The energy stored in a given capacitor is given by
E = 1/2 CV2 = 1/2 QV = 1/2Q2/C
Where C = the capacitance of the capacitor
Q = charge carried by the capacitor
V = p.d across the plates of the capacitor thus from the data given, C = 10μF
= 10 x 10-6F
Q = 100μc = 100 x 10-6C
∴ Energy stored = 1/2 Q2/C
2
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2
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1/2 10-3 5.0 x 10-4
The energy stored in a given capacitor is given by
E = 1/2 CV2 = 1/2 QV = 1/2Q2/C
Where C = the capacitance of the capacitor
Q = charge carried by the capacitor
V = p.d across the plates of the capacitor thus from the data given, C = 10μF
= 10 x 10-6F
Q = 100μc = 100 x 10-6C
∴ Energy stored = 1/2 Q2/C
| 10 x 10-6 |
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| 10 x 10-6 |
[/table]
1/2 10-3 5.0 x 10-4