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A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of ...

A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of the same metal that would be deposited by the currents of 1.5A flowing in 1h is
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  • A 2g
  • B 6g
  • C 10g
  • D 18g
Correct Answer: Option A
Explanation:
From Faradays Law, mass deposited during electrolysis is given by
M = ItZ
=> Z = M/(It)= __2
0.5x3x60x60




For a current of 1.5A flowing for 1h, the mass M, deposited is given by
M= ZiT
= 2 / (0.5x3x60x60) x 0.5x1x60x60 / 1
= 2.0g
M = 2.0g

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