A test tube of radius 1.0cm is loaded to 8.8g. If is placed upright in water, find the depth to which it would sink
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Correct Answer: Option A
Explanation:
Pressure = F/A = pgh, where p = density, h = depth and g = 10ms-2
But F = P x A
∴ Force exerted by the load test tube = cross-sectional Area x Pressure
i.e F = A x pgh
= 0.028m or 2.8m
Pressure = F/A = pgh, where p = density, h = depth and g = 10ms-2
But F = P x A
∴ Force exerted by the load test tube = cross-sectional Area x Pressure
i.e F = A x pgh
| A x pg |
| A x P x g |
| πr2 x p x g |
| π x (1.0-2)2 x 1000 x 10 |
= 0.028m or 2.8m