A 90cm uniform lever has a load of 30N suspended at 15cm from one of its ends.
If the fulcrum is at the center of gravity, the force that must be applied at its other end to keep it in horizontal equilibrium is
If the fulcrum is at the center of gravity, the force that must be applied at its other end to keep it in horizontal equilibrium is
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Correct Answer: Option B
Explanation:
Since the lever is a uniform one, its center of gravity will be acting half way (i.e 45cm)
∴from the principle of moments,
F x 45 = 30 x 30
∴ F = (30 x 30) / 45 = 20N
Since the lever is a uniform one, its center of gravity will be acting half way (i.e 45cm)
∴from the principle of moments,
F x 45 = 30 x 30
∴ F = (30 x 30) / 45 = 20N