A radioisotope has a decay constant of 10\(^{-7}\)s\(^{-1}\). The average life of the radioisotope is
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Correct Answer: Option B
Explanation:
Average life / Half life (T\(_{\frac{1}{2}}\)) = ln2/λ = 0.693/10\(^{-7}\)
= 0.693 x 10\(^7\)
= 6.93 x 10\(^6\)
Average life / Half life (T\(_{\frac{1}{2}}\)) = ln2/λ = 0.693/10\(^{-7}\)
= 0.693 x 10\(^7\)
= 6.93 x 10\(^6\)