A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor,The loss voltage of the cell is
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Correct Answer: Option B
Explanation:
E = V + v
where E = emf of cell.
V = terminal p.d
v = loss voltage of the cell.
But from ohm's law V=IR ; v = Iv
\( \implies \) lost voltage = V = Ir
= 4 x 0.5
= 2.0v
E = V + v
where E = emf of cell.
V = terminal p.d
v = loss voltage of the cell.
But from ohm's law V=IR ; v = Iv
\( \implies \) lost voltage = V = Ir
= 4 x 0.5
= 2.0v