The electric field intensity in a place where a charge of 10-10c experiences a force of 0.4N is?
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Correct Answer: Option D
Explanation:
The electric force experienced in an electric field of intensity E is given by:
F = qE: where q = the test charge.
E = F/Q = 0.4/10-10 = 0.4 X 10-10
= 4.0 X 109 NC-1
The electric force experienced in an electric field of intensity E is given by:
F = qE: where q = the test charge.
E = F/Q = 0.4/10-10 = 0.4 X 10-10
= 4.0 X 109 NC-1