An explosion occurs at an altitude of 312 m above the ground. If the air temperature is -10.00°C, how long does it take the sound to reach the ground?
[velocity of sound at \(0^oC\) = 331 ms-1]
[velocity of sound at \(0^oC\) = 331 ms-1]
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Correct Answer: Option B
Explanation:
d=312m.,T =263\(-10^°c\) = -10+273K = 263K, t=?
v= 331√ \(\frac{T}{273}\)
⇒ v = 331×√ \(\frac{263}{273}\)
⇒ v = 324.88 \(ms^-1\)
⇒ v = \(\frac{d}{t}\)
t = \(\frac{d}{t}\) = \(\frac {312}{324.88}\)
t = 0.96s
d=312m.,T =263\(-10^°c\) = -10+273K = 263K, t=?
v= 331√ \(\frac{T}{273}\)
⇒ v = 331×√ \(\frac{263}{273}\)
⇒ v = 324.88 \(ms^-1\)
⇒ v = \(\frac{d}{t}\)
t = \(\frac{d}{t}\) = \(\frac {312}{324.88}\)
t = 0.96s