A lorry accelerates uniformly in a straight line with acceleration of \(4ms^-2\) and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
We first find the lorry's initial velocity
a = \(4ms^-2\), s= 250m, t= 10, u=?
⇒ ut + \(\frac{1}{2}×4×(10^2)
⇒250= 10u + 200
⇒ 250-200 = 10u
⇒ 50 = 10u
⇒U =\frac{50}{10}\) = \(5ms^-1\)
For the next 10s, we set t=20s
= s = (5 × 20) + \(\frac{1}{2}×4×{20^2}\)
= s = 100 + 800
⇒ 900 m
;Distance covered:900-250 =650m
We first find the lorry's initial velocity
a = \(4ms^-2\), s= 250m, t= 10, u=?
⇒ ut + \(\frac{1}{2}×4×(10^2)
⇒250= 10u + 200
⇒ 250-200 = 10u
⇒ 50 = 10u
⇒U =\frac{50}{10}\) = \(5ms^-1\)
For the next 10s, we set t=20s
= s = (5 × 20) + \(\frac{1}{2}×4×{20^2}\)
= s = 100 + 800
⇒ 900 m
;Distance covered:900-250 =650m