What is the amount of heat required to raise the temperature of a 0.02 kg of ice cube from \(-10^oC\) to \(10^oC\) ?
[specific latent heat of fusion of ice = 3.34 x \(10^5\) \(Jkg^-1\), Specific heat capacity of water = 4200 \(Jkg^-1\) \(k^-1\)
Specific heat capacity of ice = 2100 \(Jkg^-1\) \(k^-1\)
[specific latent heat of fusion of ice = 3.34 x \(10^5\) \(Jkg^-1\), Specific heat capacity of water = 4200 \(Jkg^-1\) \(k^-1\)
Specific heat capacity of ice = 2100 \(Jkg^-1\) \(k^-1\)
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Correct Answer: Option D
Explanation:
Quantity of heat required to raise the temperature of the ice cube from \(-10^oC\) to \(0^oC\)
⇒H=mcâ–ºø = 0.02 × 2100 × 0 -(-10)
⇒ H = 0.02 × 2100 × (0 + 10) = 0.02 × 2100 × 10
⇒ H = 420 J
quantity of heat required to melt ice at \(0^oC\)
⇒ H = mL = 0.02 × 3.34 × \(10^5\)
⇒H=6680 j
Quantity of heat required to raise the temperature of the melted ice cube (water) from \(0^oC\) to \(-10^oC\)
⇒H=mcâ–ºø = 0.02 × 4200 × (10-0)
⇒H = 0.02 × 4200 × 10
⇒H = 840j
;420 + 6680 + 840 = 7940 j
Quantity of heat required to raise the temperature of the ice cube from \(-10^oC\) to \(0^oC\)
⇒H=mcâ–ºø = 0.02 × 2100 × 0 -(-10)
⇒ H = 0.02 × 2100 × (0 + 10) = 0.02 × 2100 × 10
⇒ H = 420 J
quantity of heat required to melt ice at \(0^oC\)
⇒ H = mL = 0.02 × 3.34 × \(10^5\)
⇒H=6680 j
Quantity of heat required to raise the temperature of the melted ice cube (water) from \(0^oC\) to \(-10^oC\)
⇒H=mcâ–ºø = 0.02 × 4200 × (10-0)
⇒H = 0.02 × 4200 × 10
⇒H = 840j
;420 + 6680 + 840 = 7940 j