Light of wavelength 589 nm in vacuum passes through a piece of fused quartz of index of refraction n = 1.458. What is the frequency of the light in fused quartz?
[Speed of light c = \(3.00×10^8 ms^{-1}\)]
[Speed of light c = \(3.00×10^8 ms^{-1}\)]
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Correct Answer: Option B
Explanation:
n=1.458, c=\(3.00 ×10^8 ms^-1\) ,λo = 589nm; f=?
Speed of light in a medium (v)=\(\frac{c}{n}\) where n is the refractive index of the medium
⇒λn=\(\frac{589}{1.458}\) = 404nm
v=fλ
⇒f=\(\frac{v}{λ}\)
=\(\frac{2.06×10^8}{404×10^-9}\) \(1nano=10^{-9}\)
∴f=\(5.09×10^{14}\) Hz
n=1.458, c=\(3.00 ×10^8 ms^-1\) ,λo = 589nm; f=?
Speed of light in a medium (v)=\(\frac{c}{n}\) where n is the refractive index of the medium
⇒λn=\(\frac{589}{1.458}\) = 404nm
v=fλ
⇒f=\(\frac{v}{λ}\)
=\(\frac{2.06×10^8}{404×10^-9}\) \(1nano=10^{-9}\)
∴f=\(5.09×10^{14}\) Hz