A charge 50 µc has electric field strength of 360 NC-1 at a certain point. The electric field strength due to another charge 120 µc kept at the same distance apart and in the same medium is?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
In general, electric field strength E = (F)/q
E = \(\frac{q}{4\pi\varepsilon_0d^2}\)
⇒ 360 = \(\frac{9\times10^9\times50\times10^-6}{d^2}\)
solving, we have \(d^2\) = 1250
putting \(d^2\) = 1250 into the second equation,
E = \(\frac{9\times10^9\times120\times10^-6}{1250}\)
we have E = \(864NC^-1\)Â
In general, electric field strength E = (F)/q
E = \(\frac{q}{4\pi\varepsilon_0d^2}\)
⇒ 360 = \(\frac{9\times10^9\times50\times10^-6}{d^2}\)
solving, we have \(d^2\) = 1250
putting \(d^2\) = 1250 into the second equation,
E = \(\frac{9\times10^9\times120\times10^-6}{1250}\)
we have E = \(864NC^-1\)Â