An object of mass 80 kg is pulled on a horizontal rough ground by a force of 500 N. Find the coefficient of static friction.
[g = 10 ms-2]
[g = 10 ms-2]
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
coefficient of friction = (F)/R = (F)/ mg = (500)/80 x 10
= 0.625
coefficient of friction = (F)/R = (F)/ mg = (500)/80 x 10
= 0.625