If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
Work done on a stretched cord
= Average force x extension
= (10 + 0)/2 x 1.2 x 10-2
= 6.0 x 10-2J
Work done on a stretched cord
= Average force x extension
= (10 + 0)/2 x 1.2 x 10-2
= 6.0 x 10-2J