If the decay constant of a radioactive substance is 0.231s1, the half-life is?
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Correct Answer: Option A
Explanation:
Half-life, T (1)/2 = (0.693)/∆ = (0.693)/ 0.231 = 3.0sec
Half-life, T (1)/2 = (0.693)/∆ = (0.693)/ 0.231 = 3.0sec