Calculate the e.m.f of the cell in the above circuit if its internal resistance is negligible
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Correct Answer: Option B
Explanation:
1/R = 1/R[sub]1[/sub] + 1/R[sub]2[/sub] = 1/3 + 1/6
= 3/6
∴ R = 6/3 = 2
E = I(R + r) = 4(2 + 0) = 8v
1/R = 1/R[sub]1[/sub] + 1/R[sub]2[/sub] = 1/3 + 1/6
= 3/6
∴ R = 6/3 = 2
E = I(R + r) = 4(2 + 0) = 8v