The density of a certain oil on frying becomes 0.4 kgm\(^{-3}\) with the volume of 20m\(^{3}\). what will be its initial volume when its initial density is 0.8 kgm\(^{-3}\) assuming no loss of oil due to spillage?
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Correct Answer: Option B
Explanation:
Density (D) = \(\frac{mass}{volume}\)
\(\therefore Mass = Density \times volume\)
= \(0.4 \times 20 = 8kg\)
The initial volume = \(\frac{Mass}{\text{Initial density}}\)
= \(\frac{8}{0.8} = 10m^{3}\)
Density (D) = \(\frac{mass}{volume}\)
\(\therefore Mass = Density \times volume\)
= \(0.4 \times 20 = 8kg\)
The initial volume = \(\frac{Mass}{\text{Initial density}}\)
= \(\frac{8}{0.8} = 10m^{3}\)