The ground stated energy for the hydrogen atom is 5.44 x 10-19J . If an electron drops from zero energy to ground state, calculate the frequency of the emitted radiation.
[h = 6.6 x 10-34 Js]
[h = 6.6 x 10-34 Js]
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Correct Answer: Option E
Explanation:
∆E = hf
f = (∆E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014
∆E = hf
f = (∆E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014