A machine of velocity ratio 6 requires an effort of 400 N to raise a load of 800 N through I m. Find the efficiency of the machine
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Correct Answer: Option C
Explanation:
Efficiency = (MA)/V.R x 100% = (load)/Effort x (1)/V.R
= (800)/400 x (1)/6 x 100% = 33.3%
Efficiency = (MA)/V.R x 100% = (load)/Effort x (1)/V.R
= (800)/400 x (1)/6 x 100% = 33.3%