In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?
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Correct Answer: Option A
Explanation:
Thrust = pressure x area = 100 pa x 3 m2 = 300 N
Thrust = pressure x area = 100 pa x 3 m2 = 300 N