A length of wire has a frequency of 255Hz when stretched by a force of b225N. If the fore increased to 324N, what is the new frequency of vibration
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Correct Answer: Option A
Explanation:
f1 = 255Hz, T1 = 225N
f2 = ? T2 = 324N
But f ∠√T => f = K√T
=> K = f/√T
∴ f1/√T[sub]1[/sub] = f2/√T[sub]2[/sub]225/√225 = f2/√324
= 306Hz
f1 = 255Hz, T1 = 225N
f2 = ? T2 = 324N
But f ∠√T => f = K√T
=> K = f/√T
∴ f1/√T[sub]1[/sub] = f2/√T[sub]2[/sub]225/√225 = f2/√324
| √225 |
| __15 |
= 306Hz