A cell of internal resistance 1Ω supplies current to an external resistor of 3Ω. The efficiency of the cell is
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Correct Answer: Option D
Explanation:
Efficiency = Output/input x 100/1
Efficiency = 3/(3+1) x 100/1
= 3/4 x 100/1 = 75%
Efficiency = Output/input x 100/1
Efficiency = 3/(3+1) x 100/1
= 3/4 x 100/1 = 75%