A simple pendulum of length 0.4m has a period of 2s. What is the period a similar pendulum of length 0.8m at the same place?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
T2 = \(\sqrt{\frac{L^2 \times T_1^2}{L_1}}\)
= \(\sqrt{\frac{0.8 \times 2^2}{0.4}}\)
= 2\(\sqrt{2}s\)
T2 = \(\sqrt{\frac{L^2 \times T_1^2}{L_1}}\)
= \(\sqrt{\frac{0.8 \times 2^2}{0.4}}\)
= 2\(\sqrt{2}s\)