Calculate the force acting on an electron of charge 1.5 x 10-19C placed in an electric field of intensity 105Vm-1
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Correct Answer: Option D
Explanation:
F = qE
F = 1.5 x 10-19 x 105
F = 1.5 x 10-14N
F = qE
F = 1.5 x 10-19 x 105
F = 1.5 x 10-14N