A radioactive source emits X—rays of very short wavelength (10 -13m ) what is the frequently of these rays?
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Correct Answer: Option C
Explanation:
\(Wavelength (\lambda) = 10^{-13}m\)
Speed of X-ray = speed of light \(C = 3×10^{8}m/s\)
Frequently (f) = ?
\(Using V = f\lambda (or (– f π for electromagnetic wave)\)
\(f = \frac{c}{\lambda} = 3 \times 10^{8} ÷ 10^{-13} = 3 \times 10^{8} \times 10^{13}\)
= \(3 \times 10^{8} \times 10^{13}\)
= \(3 \times 10^{21}Hz\)
\(Wavelength (\lambda) = 10^{-13}m\)
Speed of X-ray = speed of light \(C = 3×10^{8}m/s\)
Frequently (f) = ?
\(Using V = f\lambda (or (– f π for electromagnetic wave)\)
\(f = \frac{c}{\lambda} = 3 \times 10^{8} ÷ 10^{-13} = 3 \times 10^{8} \times 10^{13}\)
= \(3 \times 10^{8} \times 10^{13}\)
= \(3 \times 10^{21}Hz\)