A satellite moves in a circular orbit of radius 4R round the earth. The acceleration of the satellite in terms of g is
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Correct Answer: Option A
Explanation:
\(\frac{g}{R^2}\) = \(\frac{g}{4^2}\) = \(\frac{g}{16}\)
\(\frac{g}{R^2}\) = \(\frac{g}{4^2}\) = \(\frac{g}{16}\)