A radioactive isotope has a decay constant of 10-6s-1.
Calculate its half - life?
Calculate its half - life?
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Correct Answer: Option B
Explanation:
t1/2 = \(\frac{0.693}{\gamma}\) = \(\frac{0.693}{10^-6}\)
= 6.93 x 107
t1/2 = \(\frac{0.693}{\gamma}\) = \(\frac{0.693}{10^-6}\)
= 6.93 x 107