Three 3ω resistance are connected in parallel what is the equivalent resistance?
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Correct Answer: Option A
Explanation:
Resistor connected in a parallel have an equivalence given by
\(\frac{1}{\text{Reff}}\) = \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)
= \(\frac{1 + 1 + 1}{3}\) = \(\frac{3}{3}\) = 1
Reff = 1ω
Resistor connected in a parallel have an equivalence given by
\(\frac{1}{\text{Reff}}\) = \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)
= \(\frac{1 + 1 + 1}{3}\) = \(\frac{3}{3}\) = 1
Reff = 1ω