Determine the focal length of a thin converging lens if the power is 5.0 dioptres
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
Power of a lens = \(\frac{1}{f}\)
f = focal length
f = \(\frac{1}{p}\)
= \(\frac{1}{5}\)
= 0.2m
Power of a lens = \(\frac{1}{f}\)
f = focal length
f = \(\frac{1}{p}\)
= \(\frac{1}{5}\)
= 0.2m