A mass of 0.5kg is whirled in a vertical circle of radius 2m at a steady rate of 2 rev/s. Calculate the centripetal force
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
ω = 2πF = 2π × 2 = 4πrad\(^{-1}\)Centripetal force = mrω\(^2\)⇒ 0.5 × 2 × (4π)\(^2\)⇒ 160N
ω = 2πF = 2π × 2 = 4πrad\(^{-1}\)Centripetal force = mrω\(^2\)⇒ 0.5 × 2 × (4π)\(^2\)⇒ 160N