The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
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Correct Answer: Option A
Explanation:
Mr(90 - 50) = 0.2(100 - 90)
40Mr = 0.2 × 10
Mr= 2/40 = 0.05kg
Mr(90 - 50) = 0.2(100 - 90)
40Mr = 0.2 × 10
Mr= 2/40 = 0.05kg