An object is placed 20cm from a concave mirror of focal length 10cm. The linear magnification of the image produced is?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
\(\frac{I}{V}\) = \(\frac{1}{f}\) – \(\frac{1}{u}\)
\(\frac{I}{V}\) = \(\frac{1}{10}\) – \(\frac{1}{20}\)
 = \(\frac{1}{20}\) V
 V = 20cm.
 M = \(\frac{V}{U}\)
 = \(\frac{20}{20}\)
 = 1
\(\frac{I}{V}\) = \(\frac{1}{f}\) – \(\frac{1}{u}\)
\(\frac{I}{V}\) = \(\frac{1}{10}\) – \(\frac{1}{20}\)
 = \(\frac{1}{20}\) V
 V = 20cm.
 M = \(\frac{V}{U}\)
 = \(\frac{20}{20}\)
 = 1