A man hears his echo from a nearby hill 2s after he shouted. If the frequency of his voice is 260Hz and the wavelength is 1.29m, how far away is the hill?
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Correct Answer: Option B
Explanation:
Recall V = F × \(\lambda\)
= 260 × 1.29
= 335.4ms\(^{-1}\)
Echo time = \(\frac{2}{2}\) = 1 sec
Distance = v x t = 335.4 x 1
= 335.4m
Recall V = F × \(\lambda\)
= 260 × 1.29
= 335.4ms\(^{-1}\)
Echo time = \(\frac{2}{2}\) = 1 sec
Distance = v x t = 335.4 x 1
= 335.4m