The efficiency of energy conversion on the energy flow through a hydroelectric power is?
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Correct Answer: Option B
Explanation:
Efficiency = \(\frac{\text{useful energy output from machine}}{\text{energy input into machine}}\)
= \(\frac{E3}{E2}\)
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Efficiency = \(\frac{\text{useful energy output from machine}}{\text{energy input into machine}}\)
= \(\frac{E3}{E2}\)
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