The image of an object is located 6cm behind a convex mirror. If it's magnification is 0.6, calculate the focal length of the mirror
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Correct Answer: Option
Explanation:
V = 6cm
 M = 6cm
 Recall m = U = \(\frac{V}{U}\)
 U = \(frac{V}{M}\)
 =U = \(\frac{6}{0.6}\)
 U = 10
 \(\frac{1}{U}\) + \(\frac{1}{V}\) = \(\frac{1}{F}\)
 \(\frac{1}{10}\) + \(\frac{1}{6}\)
= \(\frac{1}{F}\)
 6 + \(\frac{10}{60}\)
\(\frac{16}{60}\) = \(\frac{1}{F}\)
 F = \(\frac{60}{16}\)
=Â 3.75cm
V = 6cm
 M = 6cm
 Recall m = U = \(\frac{V}{U}\)
 U = \(frac{V}{M}\)
 =U = \(\frac{6}{0.6}\)
 U = 10
 \(\frac{1}{U}\) + \(\frac{1}{V}\) = \(\frac{1}{F}\)
 \(\frac{1}{10}\) + \(\frac{1}{6}\)
= \(\frac{1}{F}\)
 6 + \(\frac{10}{60}\)
\(\frac{16}{60}\) = \(\frac{1}{F}\)
 F = \(\frac{60}{16}\)
=Â 3.75cm