A solid weighs 45N and 15N respectively in air and water. Determine the relative density of the solid
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
Weight in Air = 45N
 Weight in Water = 15N
 R.D = \(\frac{\text{Weight in Air}}{\text{Weight in water}}\)
 R.D = \(\frac{45}{15}\) = 3.00
Weight in Air = 45N
 Weight in Water = 15N
 R.D = \(\frac{\text{Weight in Air}}{\text{Weight in water}}\)
 R.D = \(\frac{45}{15}\) = 3.00