A vibrator causes water ripples to travel across the surface of a tank. The wave travels 50cm in 2s and the distance between successive crests is 5cm. Calculate the frequency of the vibrator
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
\(V = \frac{Distance}{time}\)
= \(\frac{50cm}{2s}\)
= 25 cms\(^{-1}\).
\(V = f \lambda\)
\(f = \frac{V}{\lambda}\)
\(f = \frac{25}{5}\)
= 5 Hz
Â
\(V = \frac{Distance}{time}\)
= \(\frac{50cm}{2s}\)
= 25 cms\(^{-1}\).
\(V = f \lambda\)
\(f = \frac{V}{\lambda}\)
\(f = \frac{25}{5}\)
= 5 Hz
Â