The earth's gravitational field intensity at its surface is about
(G = 6.7 à— 10\(^{-11}\)Nm\(^2\)/kg\(^2\), mass of the earth is 6 à— 10\(^{24}\)kg, radius of the earth is 6.4 à— 10\(^6\)m, g on the earth = 9.8m/s\(^2\))
(G = 6.7 à— 10\(^{-11}\)Nm\(^2\)/kg\(^2\), mass of the earth is 6 à— 10\(^{24}\)kg, radius of the earth is 6.4 à— 10\(^6\)m, g on the earth = 9.8m/s\(^2\))
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
E
=
F
m
=
GMm/d\(^2\)
m
=
GM
d\(^2\)
Â
E
=
6.7 × 10\(^{-11}\) × 6 × 10\(^{24}\)
(6.4 × 10\(^6\))\(^2\)
=
9.8N
kg
E = g = 9.8N/kg
E
=
F
m
=
GMm/d\(^2\)
m
=
GM
d\(^2\)
Â
E
=
6.7 × 10\(^{-11}\) × 6 × 10\(^{24}\)
(6.4 × 10\(^6\))\(^2\)
=
9.8N
kg
E = g = 9.8N/kg