A force of 6N acts horizontally on a stationary mass of 2kg for 4s. The kinetic energy gained by the mass is _________
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Correct Answer: Option n
Explanation:
F = 6N, m = 2kg, t = 4s, u = 0 (stationary or at rest)
K.E
=
1
2
mv\(^2\)
F
=
mv
t
from rest
K.E
=
1
2
m(
Ft
m
)\(^2\)
=
1
2
×
2 x (\(\frac{6 \times 4}{2})^2 = 12^2 = 144J\)
F = 6N, m = 2kg, t = 4s, u = 0 (stationary or at rest)
K.E
=
1
2
mv\(^2\)
F
=
mv
t
from rest
K.E
=
1
2
m(
Ft
m
)\(^2\)
=
1
2
×
2 x (\(\frac{6 \times 4}{2})^2 = 12^2 = 144J\)