Three resistors with resistance 200Ω, 500Ω and 1kΩ are connected in series. A 6v battery is connected to either end of the combination. Calculate the potential difference between the ends of 200Ω resistance.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
Â
Req = 200 + 500 + 1000 = 1700Ω
P.d
(across
200Ω)
=
200
1700
×
6
=
0.71V
Â
Req = 200 + 500 + 1000 = 1700Ω
P.d
(across
200Ω)
=
200
1700
×
6
=
0.71V