The length of the seconds hand of laboratory clock is 0.1m. Calculate the speed at the top of the seconds hand
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Correct Answer: Option
Explanation:
Length of the seconds hand = r = 0.1m but the seconds hand rotates through 360° or 2π rad in 60s.
Thus,
ω
=
θ
=
2Ï€
60
Velocity of the tip of the hand, V = ωr
V
=
2Ï€
60
×
0.1
=
2Ï€
600
=
Ï€
300
=
3.142
300
V = 0.01047 = 1.05 × 10\(^{-2}\)ms\(^{-1}\)
Length of the seconds hand = r = 0.1m but the seconds hand rotates through 360° or 2π rad in 60s.
Thus,
ω
=
θ
=
2Ï€
60
Velocity of the tip of the hand, V = ωr
V
=
2Ï€
60
×
0.1
=
2Ï€
600
=
Ï€
300
=
3.142
300
V = 0.01047 = 1.05 × 10\(^{-2}\)ms\(^{-1}\)