A gas occupies volume \( 200cm^3 \) at \( 300K \). Determine volume at \( 450K \).
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
Charles’ law: \( \dfrac{V_1}{T_1} = \dfrac{V_2}{T_2} \) \( \dfrac{200}{300} = \dfrac{V_2}{450} \) \( V_2 = 300cm^3 \) Therefore, the volume becomes \( 300cm^3 \).
Charles’ law: \( \dfrac{V_1}{T_1} = \dfrac{V_2}{T_2} \) \( \dfrac{200}{300} = \dfrac{V_2}{450} \) \( V_2 = 300cm^3 \) Therefore, the volume becomes \( 300cm^3 \).