The half-life of radioactive substance is \( 4 \) days. Determine fraction remaining after \( 12 \) days.
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Correct Answer: Option A
Explanation:
Number of half-lives: \( \dfrac{12}{4} = 3 \) Remaining fraction: \( \left(\dfrac12\right)^3 = \dfrac18 \) Therefore, \( \dfrac18 \) remains.
Number of half-lives: \( \dfrac{12}{4} = 3 \) Remaining fraction: \( \left(\dfrac12\right)^3 = \dfrac18 \) Therefore, \( \dfrac18 \) remains.