Determine photon energy for frequency \( 4 \times 10^{14}Hz \).<br/>\( h = 6.63 \times 10^{-34}Js \)
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Correct Answer: Option C
Explanation:
Photon energy: \( E = hf \) \( E = 6.63 \times 10^{-34} \times 4 \times 10^{14} \) \( E = 2.65 \times 10^{-19}J \) Therefore, photon energy is \( 2.65 \times 10^{-19}J \).
Photon energy: \( E = hf \) \( E = 6.63 \times 10^{-34} \times 4 \times 10^{14} \) \( E = 2.65 \times 10^{-19}J \) Therefore, photon energy is \( 2.65 \times 10^{-19}J \).