A battery of emf 24V and internal resistance 4Ω is connected to a resistor of 32Ω. What is the terminal p.d of the battery?
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Correct Answer: Option B
Explanation:
E = V + Ir
V = E- Ir
V = 24 - {(24/36) x 4}
V = 21.3V
E = V + Ir
V = E- Ir
V = 24 - {(24/36) x 4}
V = 21.3V