An object R leaves a platform XY with a horizontal velocity of 7m-1 and lands at Q. lf it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ.(Take g = 1Oms2)
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Correct Answer: Option C
Explanation:
D = v x t = 7 x 0.3 = 2.1m
D = v x t = 7 x 0.3 = 2.1m