A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
I =
E/R + r
=
1.5/2.5 + 0.5 + 7
= 0.15
I =
E/R + r
=
1.5/2.5 + 0.5 + 7
= 0.15