How long will it take to heat 3 kg of water from 28oC to 88oC in an electric taking a current of 6 A from an e.m.f. source of 220V?
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Correct Answer: Option C
Explanation:
Ivt = mcΔθt =
mcΔθ/Iv
=
3x 4200 x (88 - 28)/6 x 200
Ivt = mcΔθt =
mcΔθ/Iv
=
3x 4200 x (88 - 28)/6 x 200