A wire, 20m long is heated from a temperature of 5oC to 55oC. If the change in length is 0.020m, calculate the linear expansivity of the wire
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
\(\alpha = \frac{\Delta L}{L \Delta \theta} = \frac{0.020}{20 \times (55 - 5)} = 2.0 \times 10^{-5}\)
\(\alpha = \frac{\Delta L}{L \Delta \theta} = \frac{0.020}{20 \times (55 - 5)} = 2.0 \times 10^{-5}\)